In above case, Thread- has A but need B to complete processing and Similarly Thread-2 has resource B but need A first.
Let write above scenario in java code:
Let write above scenario in java code:
package thread;
public class ResolveDeadLockTest {
public static void main(String[] args) {
ResolveDeadLockTest test = new ResolveDeadLockTest();
final A a = test.new A();
final B b = test.new B();
// Thread-1
Runnable block1 = new Runnable() {
public void run() {
synchronized (a) {
try {
// Adding delay so that both threads can start trying to
// lock resources
Thread.sleep(100);
} catch (InterruptedException e) {
e.printStackTrace();
}
// Thread-1 have A but need B also
synchronized (b) {
System.out.println("In block 1");
}
}
}
};
// Thread-2
Runnable block2 = new Runnable() {
public void run() {
synchronized (b) {
// Thread-2 have B but need A also
synchronized (a) {
System.out.println("In block 2");
}
}
}
};
new Thread(block1).start();
new Thread(block2).start();
}
// Resource A
private class A {
private int i = 10;
public int getI() {
return i;
}
public void setI(int i) {
this.i = i;
}
}
// Resource B
private class B {
private int i = 20;
public int getI() {
return i;
}
public void setI(int i) {
this.i = i;
}
}
}
Running above code will result in deadlock for very obvious reasons (explained above). Now we have to solve this issue.
I believe, solution to any problem lies in identifying the root of problem. In our case, it is the pattern of accessing A and B, is main issue. So, to solve it, we will simply re-order the statements where code is accessing shared resources.
After rewriting the code, it will look like this ::
I believe, solution to any problem lies in identifying the root of problem. In our case, it is the pattern of accessing A and B, is main issue. So, to solve it, we will simply re-order the statements where code is accessing shared resources.
After rewriting the code, it will look like this ::
// Thread-1Run again above class, and you will not see any deadlock kind of situation. I hope, it will help you in avoiding deadlocks, and if encountered, in resolving them.
Runnable block1 = new Runnable() {
public void run() {
synchronized (b) {
try {
// Adding delay so that both threads can start trying to
// lock resources
Thread.sleep(100);
} catch (InterruptedException e) {
e.printStackTrace();
}
// Thread-1 have A but need B also
synchronized (a) {
System.out.println("In block 1");
}
}
}
};
// Thread-2
Runnable block2 = new Runnable() {
public void run() {
synchronized (b) {
// Thread-2 have B but need A also
synchronized (a) {
System.out.println("In block 2");
}
}
}
};
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Source:http://www.tutorialsdesk.com/2014/08/writing-deadlock-and-resolving-in-java.html
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